A transistor is used as a common emitter ampl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The voltage gain $(A_v)$ of a common emitter amplifier is given by the formula: $A_v = \beta 	imes \frac{R_L}{R_i}$,where $\beta = \frac{\Delta I

Vedclass · Accepted Answer

$1000$

Vedclass · Answer

(B) The voltage gain $(A_v)$ of a common emitter amplifier is given by the formula: $A_v = \beta 	imes \frac{R_L}{R_i}$,where $\beta = \frac{\Delta I_C}{\Delta I_B}$.Given:Load resistance $(R_L)$ = $2 \ k\Omega = 2000 \ \Omega$.Input resistance $(R_i)$ = $150 \ \Omega$.Change in base current $(\Delta I_B)$ = $20 \ \mu A = 20 	imes 10^{-6} \ A$.Change in collector current $(\Delta I_C)$ = $1.5 \ mA = 1.5 	imes 10^{-3} \ A$.First,calculate the current gain $(\beta)$:$\beta = \frac{1.5 	imes 10^{-3}}{20 	imes 10^{-6}} = \frac{1.5}{20} 	imes 10^3 = 0.075 	imes 1000 = 75$.Now,calculate the voltage gain $(A_v)$:$A_v = 75 	imes \frac{2000}{150} = 75 	imes \frac{40}{3} = 25 	imes 40 = 1000$.

$A$ transistor is used as a common emitter amplifier with a load resistance of $2 \ k\Omega$. The input resistance is $150 \ \Omega$. Base current is changed by $20 \ \mu A$,which results in a change in collector current by $1.5 \ mA$. The voltage gain of the amplifier is

Similar Questions

$A$ point moves in the $xy$-plane such that the sum of its distances from two mutually perpendicular lines is always equal to $5$ units. The area (in sq units) enclosed by the locus of the point is

If the line $ax + by + c = 0$ is a normal to the curve $xy = 1$,then

Assertion $A$: Barium is not required in the normal biological processes of the human body.
Reason $R$: Barium does not exhibit more than one oxidation state.

The $emf$ (in $V$) of a Daniell cell containing $0.1 \ M$ $ZnSO_4$ and $0.01 \ M$ $CuSO_4$ solutions at their respective electrodes is
$(E_{Cu^{2+} / Cu}^{\circ} = +0.34 \ V; E_{Zn^{2+} / Zn}^{\circ} = -0.76 \ V)$

Photoelectric emission is observed from a metallic surface for frequencies $v_1$ and $v_2$ of the incident light $(v_1 > v_2)$. If the maximum values of kinetic energy of the photoelectrons emitted in the two cases are in the ratio $1: n$,then the threshold frequency of the metallic surface is

Vedclass Test Series

Exam Paper Generator

Online Exam Module