A metal rod 2 ,m long increases in length by | vedclass

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Question

$(A)$ The formula for the coefficient of linear expansion is given by $\alpha = \frac{\Delta L}{L_1 \Delta T}$.Given:Initial length $L_1 = 2 \,m$.Chan

Vedclass · Accepted Answer

$1.33 	imes 10^{-5} /{ }^{\circ} C$

Vedclass · Answer

$(A)$ The formula for the coefficient of linear expansion is given by $\alpha = \frac{\Delta L}{L_1 \Delta T}$.Given:Initial length $L_1 = 2 \,m$.Change in length $\Delta L = 1.6 \,mm = 1.6 	imes 10^{-3} \,m$.Change in temperature $\Delta T = 60^{\circ} C - 0^{\circ} C = 60^{\circ} C$.Substituting these values into the formula:$\alpha = \frac{1.6 	imes 10^{-3}}{2 	imes 60}$$\alpha = \frac{1.6 	imes 10^{-3}}{120}$$\alpha = \frac{1.6}{120} 	imes 10^{-3} = 0.01333 	imes 10^{-3} = 1.33 	imes 10^{-5} /{ }^{\circ} C$.Therefore, the correct option is $A$.

$A$ metal rod $2 \,m$ long increases in length by $1.6 \,mm$, when heated from $0^{\circ} C$ to $60^{\circ} C$. The coefficient of linear expansion of the metal rod is:

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