(B) The fringe width $\beta$ in a medium of refractive index $\mu$ is given by $\beta = \frac{\lambda_w D}{d}$.Here, the wavelength in water is $\lamb

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) The fringe width $\beta$ in a medium of refractive index $\mu$ is given by $\beta = \frac{\lambda_w D}{d}$.Here, the wavelength in water is $\lambda_w = \frac{\lambda_{air}}{\mu} = \frac{6300 \times 10^{-10} \,m}{1.33}$.Given: $D = 1.33 \,m$, $d = 1 \,mm = 10^{-3} \,m$, and $\mu = 1.33$.Substituting these values into the formula:$\beta = \frac{(6300 \times 10^{-10} / 1.33) \times 1.33}{10^{-3}} \,m$.$\beta = \frac{6300 \times 10^{-10}}{10^{-3}} \,m$.$\beta = 6300 \times 10^{-7} \,m = 6.3 \times 10^{-4} \,m$.

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

Medium

$A$ double slit experiment is immersed in water of refractive index $1.33$. The slit separation is $1 \,mm$, and the distance between the slit and the screen is $1.33 \,m$. The slits are illuminated by light of wavelength $6300 \,Å$. The fringe width is:

MHT CET 2020 All MHT CET

A
$6.9 \times 10^{-4} \,m$
B
$6.3 \times 10^{-4} \,m$
C
$5.8 \times 10^{-4} \,m$
D
$8.6 \times 10^{-4} \,m$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Wave Optics

Subtopic

Young's Double Slit Experiment (YDSE)

Previous Year

MHT CET 2020 Paper All MHT CET years →

Two parallel slits $0.6 \,mm$ apart are illuminated by a light source of wavelength $6000 \,\mathring{A}$. The distance between two consecutive dark fringes on a screen $1 \,m$ away from the slits is:

Medium

View Solution

Young's double-slit experiment is carried out by using green,red,and blue light,one color at a time. The fringe widths recorded are $\beta_G$,$\beta_R$,and $\beta_B$ respectively. Then:

Medium

View Solution

In an interference experiment,the distance between a maximum and the adjacent minimum is .......

Easy

View Solution

In a Young's double slit experiment,the intensity at a point where the path difference is $\frac{\lambda}{6}$ ($\lambda$ being the wavelength of the light used) is $I$. If $I_0$ denotes the maximum intensity,$I/I_0$ is equal to

Difficult

View Solution

In a Young's double slit experiment,the angular width of a fringe formed on a distant screen is $1^{\circ}$. The wavelength of the light used is $6280 \; \mathring{A}$. The distance between the two coherent sources is $...........\,mm$.

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ double slit experiment is immersed in water of refractive index $1.33$. The slit separation is $1 \,mm$, and the distance between the slit and the screen is $1.33 \,m$. The slits are illuminated by light of wavelength $6300 \,Å$. The fringe width is:

Similar Questions

Two parallel slits $0.6 \,mm$ apart are illuminated by a light source of wavelength $6000 \,\mathring{A}$. The distance between two consecutive dark fringes on a screen $1 \,m$ away from the slits is:

Young's double-slit experiment is carried out by using green,red,and blue light,one color at a time. The fringe widths recorded are $\beta_G$,$\beta_R$,and $\beta_B$ respectively. Then:

In an interference experiment,the distance between a maximum and the adjacent minimum is .......

In a Young's double slit experiment,the intensity at a point where the path difference is $\frac{\lambda}{6}$ ($\lambda$ being the wavelength of the light used) is $I$. If $I_0$ denotes the maximum intensity,$I/I_0$ is equal to

In a Young's double slit experiment,the angular width of a fringe formed on a distant screen is $1^{\circ}$. The wavelength of the light used is $6280 \; \mathring{A}$. The distance between the two coherent sources is $...........\,mm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module