A resonance tube closed at one end is of heig | vedclass

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(D) The wavelength $\lambda$ of the sound wave is given by $\lambda = \frac{v}{f} = \frac{340}{340} = 1 \ m = 100 \ cm$.For a tube closed at one end,r

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$25$

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(D) The wavelength $\lambda$ of the sound wave is given by $\lambda = \frac{v}{f} = \frac{340}{340} = 1 \ m = 100 \ cm$.For a tube closed at one end,resonance occurs when the length of the air column $L$ is an odd multiple of $\frac{\lambda}{4}$,i.e.,$L = \frac{\lambda}{4}, \frac{3\lambda}{4}, \frac{5\lambda}{4}, \dots$The possible lengths of the air column are $25 \ cm, 75 \ cm, 125 \ cm, \dots$The total height of the tube is $150 \ cm$.To obtain resonance,the air column length must be one of the values above. To have the minimum height of the water column,we must choose the maximum possible air column length that fits in the tube,which is $125 \ cm$.Minimum height of water column $= 	ext{Total height} - 	ext{Maximum air column length} = 150 \ cm - 125 \ cm = 25 \ cm$.

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