$A$ progressive wave of frequency $400 \ Hz$ is travelling with a velocity $336 \ m/s$. How far apart are the two points which are $60^{\circ}$ out of phase (in $m$)?

The displacement equations of two waves are given as ${y_1} = 10\sin \left( {3\pi t + \frac{\pi }{3}} \right)$ and ${y_2} = 5(\sin 3\pi t + \sqrt 3 \cos 3\pi t)$. What is the ratio of their amplitudes?

$A$ wave equation which gives the displacement along the $Y$ direction is given by the equation $y = 10^4 \sin(60t + 2x)$,where $x$ and $y$ are in metres and $t$ is time in seconds. This represents a wave:

$A$ wave is given by $Y = 3 \sin 2 \pi \left( \frac{t}{0.04} - \frac{x}{0.01} \right)$ where $Y$ is in $cm$. The frequency of the wave and the maximum acceleration will be $(\pi^2 = 10)$.

$A$ transverse wave propagating along the $x-$ axis is represented by $y(x,t) = 8.0 \sin \left( 0.5\pi x - 4\pi t - \frac{\pi}{4} \right)$,where $x$ is in metres and $t$ is in seconds. The speed of the wave is ..... $m/s$.

The equation of a wave is given by $y = 10 \sin \left( \frac{2 \pi}{45} t + \alpha \right)$. If the displacement is $5 \text{ cm}$ at $t = 0$,then the total phase at $t = 7.5 \text{ s}$ is