$\int_{\frac{\pi}{6}}^{\frac{\pi}{3}} \frac{\sqrt{\cos x}}{\sqrt{\sin x}+\sqrt{\cos x}} d x$ is equal to . . . . . . .

  • A
    $\frac{\pi}{4}$
  • B
    $0$
  • C
    $\frac{\pi}{6}$
  • D
    $\frac{\pi}{12}$

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