frac{cos 17^circ + sin 17^circ}{cos 17^circ - | vedclass

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Question

(A) Dividing the numerator and the denominator by $\cos 17^\circ$,we get:$\frac{\cos 17^\circ + \sin 17^\circ}{\cos 17^\circ - \sin 17^\circ} = \frac{

Vedclass · Accepted Answer

$	an 62^\circ$

Vedclass · Answer

(A) Dividing the numerator and the denominator by $\cos 17^\circ$,we get:$\frac{\cos 17^\circ + \sin 17^\circ}{\cos 17^\circ - \sin 17^\circ} = \frac{1 + 	an 17^\circ}{1 - 	an 17^\circ}$Since $	an 45^\circ = 1$,we can write this as:$= \frac{	an 45^\circ + 	an 17^\circ}{1 - 	an 45^\circ 	an 17^\circ}$Using the formula $	an(A + B) = \frac{	an A + 	an B}{1 - 	an A 	an B}$,where $A = 45^\circ$ and $B = 17^\circ$:$= 	an(45^\circ + 17^\circ) = 	an 62^\circ$.

$\frac{\cos 17^\circ + \sin 17^\circ}{\cos 17^\circ - \sin 17^\circ} = $

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