A coil of surface area 200 cm^2 having 25 tu | vedclass

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(C) The induced charge $Q$ in a coil is given by the formula $Q = \frac{\Delta \phi}{R}$,where $\Delta \phi$ is the change in magnetic flux and $R$ is

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(C) The induced charge $Q$ in a coil is given by the formula $Q = \frac{\Delta \phi}{R}$,where $\Delta \phi$ is the change in magnetic flux and $R$ is the resistance of the coil.Given:Number of turns $N = 25$Area $A = 200 \ cm^2 = 200 	imes 10^{-4} \ m^2 = 0.02 \ m^2$Magnetic field $B = 0.02 \ Wb/m^2$Resistance $R = 1 \ \Omega$Time $t = 1 \ s$Initial flux $\phi_i = N B A \cos(0^\circ) = 25 	imes 0.02 	imes 0.02 = 0.01 \ Wb$Final flux $\phi_f = 0 \ Wb$ (since it is removed from the field)Change in flux $\Delta \phi = |\phi_f - \phi_i| = 0.01 \ Wb$Induced charge $Q = \frac{\Delta \phi}{R} = \frac{0.01 \ Wb}{1 \ \Omega} = 0.01 \ C$.

$A$ coil of surface area $200 \ cm^2$ having $25$ turns is held perpendicular to the magnetic field of intensity $0.02 \ Wb/m^2$. The resistance of the coil is $1 \ \Omega$. If it is removed from the magnetic field in $1 \ s$,the induced charge in the coil is . . . . . . $C$.

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