$A$ coil of self-inductance $0.5 \ mH$ carries a current of $2 \ A$. The energy stored in Joule is . . . . . . .

When a current of $4 \ mA$ passes through an inductor,if the flux linked with it is $32 \times 10^{-6} \ T \ m^2$,then the energy stored in the inductor is

Energy stored in a coil of self-inductance $40 \, mH$ carrying a steady current of $2 \, A$ is.....$J$

The energy stored in a $50 mH$ inductor carrying a current of $4 A$ is (in $J$)

Assertion : If the current in a solenoid is reversed in direction while keeping the same magnitude,the magnetic field energy stored in the solenoid remains unchanged.
Reason : Magnetic field energy density is proportional to the magnetic field.

The expression for the magnetic energy stored in a solenoid of length $L$, in terms of magnetic field $B$ and area $A$ is