A bulb of 800 text{ W} electrical power has a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electrical power of the bulb is $P_{elec} = 800 	ext{ W}$.The efficiency of the bulb is $\eta = 3 \% = 0.03$.The radiant power (energy emitte

Vedclass · Accepted Answer

$8 	imes 10^{-8} 	ext{ N}$

Vedclass · Answer

(B) The electrical power of the bulb is $P_{elec} = 800 	ext{ W}$.The efficiency of the bulb is $\eta = 3 \% = 0.03$.The radiant power (energy emitted per second) is $P_{rad} = P_{elec} 	imes \eta = 800 	imes 0.03 = 24 	ext{ J/s}$.The force exerted by an electromagnetic wave on a surface that absorbs it is given by $F = \frac{P_{rad}}{c}$,where $c = 3 	imes 10^8 	ext{ m/s}$ is the speed of light.Substituting the values: $F = \frac{24}{3 	imes 10^8} 	ext{ N}$.$F = 8 	imes 10^{-8} 	ext{ N}$.Thus,the correct option is $B$.

$A$ bulb of $800 \text{ W}$ electrical power has an efficiency of $3 \%$. It is kept at the centre of a sphere of diameter $20 \text{ cm}$. The force exerted on its surface by the electromagnetic $(EM)$ wave is . . . . . . .

Similar Questions

Radiations of intensity $0.5 \ Wm^{-2}$ are striking a metal plate. The pressure exerted on the plate is:

$A$ lamp delivers a luminous flux of $100 \,W$ to an absorber of area $1 \,cm^2$. The force due to radiation pressure is

The radiation pressure exerted by a $450 \ W$ light source on a perfectly reflecting surface placed at $2 \ m$ away from it is:

An astronaut floating freely in space decides to use his flashlight as a rocket. He shines a $10$ $W$ light beam in a fixed direction so that he acquires momentum in the opposite direction. If his mass is $80$ kg,how long must he shine the light to reach a velocity of $1$ $m/s$?

If electromagnetic waves of power $600 \ W$ are incident on a non-reflecting surface,then the total force acting on the surface is

Vedclass Test Series

Exam Paper Generator

Online Exam Module