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(B) The electric potential $V$ at a distance $r$ from a point charge $Q$ is given by $V = \frac{kQ}{r}$.Since the circular path is centered at $Q$,eve

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Zero

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(B) The electric potential $V$ at a distance $r$ from a point charge $Q$ is given by $V = \frac{kQ}{r}$.Since the circular path is centered at $Q$,every point on the circumference is at the same distance $r$ from the charge $Q$.Therefore,the electric potential at any point on the circular path is constant.Let $V_A$ be the potential at point $A$ and $V_B$ be the potential at point $B$. Since both points are on the circle,$V_A = V_B = \frac{kQ}{r}$.The work done $W$ in moving a charge $q$ from point $A$ to point $B$ is given by $W = q(V_B - V_A)$.Substituting the values,$W = q(\frac{kQ}{r} - \frac{kQ}{r}) = q(0) = 0$.Thus,the work done is zero.

$A$ charge $+Q$ is placed at the centre of a circular path of radius $r$. The work done to bring a charge $+q$ from one end of the diameter to the other end of the circular path in the electric field produced by charge $+Q$ is $.......$

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