A compound A (C_{7}H_{8}O) is insoluble in Na | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. The compound $A$ $(C_{7}H_{8}O)$ is insoluble in $NaHCO_{3}$ (meaning it is not a carboxylic acid) but soluble in $NaOH$ and gives a characte

Vedclass · Accepted Answer

$m$-Cresol

Vedclass · Answer

(B) $1$. The compound $A$ $(C_{7}H_{8}O)$ is insoluble in $NaHCO_{3}$ (meaning it is not a carboxylic acid) but soluble in $NaOH$ and gives a characteristic color with neutral $FeCl_{3}$ solution,which indicates the presence of a phenolic $-OH$ group.$2$. The reaction with bromine water to form a tribromo derivative $(C_{7}H_{5}OBr_{3})$ is a characteristic reaction of phenols where the ortho and para positions are substituted by bromine atoms.$3$. Among the given options,$m$-cresol ($3$-methylphenol) is a phenol that reacts with bromine water to form $2,4,6$-tribromo-$3$-methylphenol $(C_{7}H_{5}OBr_{3})$.$4$. Therefore,compound $A$ is $m$-cresol.

$A$ compound $A$ $(C_{7}H_{8}O)$ is insoluble in $NaHCO_{3}$ solution but dissolves in $NaOH$ and gives a characteristic colour with neutral $FeCl_{3}$ solution. When treated with bromine water,compound $A$ forms the compound $B$ with the formula $C_{7}H_{5}OBr_{3}$. $A$ is:

Similar Questions

The electrophile involved in the below reaction is:

Consider the following reaction:
$Phenol$ $\xrightarrow{Zn\,dust} X$ $\xrightarrow[{Anhyd.\,AlCl_3}]{CH_3Cl} Y$ $\xrightarrow{Alkaline\,KMnO_4} Z$
The product $Z$ is:

Phenol is

Phenol reacts with acetone in the presence of concentrated sulphuric acid to form a $C_{15}H_{16}O_2$ product. Which of the following compounds is this product?

Identify the product formed in the reaction.
Phenol $+$ conc. $H_2SO_4$ $\xrightarrow{373 \ K}$ product

Vedclass Test Series

Exam Paper Generator

Online Exam Module