A circular coil of radius 10 text{ cm} and 10 | vedclass

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(C) Given: Radius of the coil $r = 10 	ext{ cm} = 0.1 	ext{ m}$.Number of turns $N = 100$.Current $I = 1 	ext{ A}$.The magnetic moment $M$ of a cur

Vedclass · Accepted Answer

$3.142 	ext{ A m}^{2}$

Vedclass · Answer

(C) Given: Radius of the coil $r = 10 	ext{ cm} = 0.1 	ext{ m}$.Number of turns $N = 100$.Current $I = 1 	ext{ A}$.The magnetic moment $M$ of a current-carrying coil is given by the formula $M = N I A$,where $A$ is the area of the coil.The area $A = \pi r^{2} = \pi 	imes (0.1 	ext{ m})^{2} = 0.01 \pi 	ext{ m}^{2}$.Substituting the values into the formula:$M = 100 	imes 1 	imes (0.01 	imes 3.142) 	ext{ A m}^{2}$.$M = 100 	imes 0.03142 	ext{ A m}^{2} = 3.142 	ext{ A m}^{2}$.Thus,the magnetic moment of the coil is $3.142 	ext{ A m}^{2}$.

$A$ circular coil of radius $10 \text{ cm}$ and $100$ turns carries a current of $1 \text{ A}$. What is the magnetic moment of the coil?

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