$A$ $ 100 \,W $ bulb is connected to an $ AC $ source of $ 220 \,V, 50 \,Hz $. Then the current flowing through the bulb is

  • A
    $ \frac{5}{11} \,A $
  • B
    $ \frac{1}{2} \,A $
  • C
    $ 2 \,A $
  • D
    $ \frac{3}{4} \,A $

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