4 times 10^{10} electrons are removed from a | vedclass

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(B) Given: Number of electrons removed $n = 4 	imes 10^{10}$.Diameter of the sphere $= 20 	ext{ cm}$,so radius $R = 10 	ext{ cm} = 0.1 	ext{ m}$.D

Vedclass · Accepted Answer

$1440$

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(B) Given: Number of electrons removed $n = 4 	imes 10^{10}$.Diameter of the sphere $= 20 	ext{ cm}$,so radius $R = 10 	ext{ cm} = 0.1 	ext{ m}$.Distance from the centre $r = 20 	ext{ cm} = 0.2 	ext{ m}$.The charge $q$ on the sphere is $q = n 	imes e = 4 	imes 10^{10} 	imes 1.6 	imes 10^{-19} 	ext{ C} = 6.4 	imes 10^{-9} 	ext{ C}$.Since the point is outside the sphere $(r > R)$,the sphere acts as a point charge at its centre.The electric field $E$ is given by $E = \frac{1}{4 \pi \epsilon_0} \frac{q}{r^2}$.Substituting the values: $E = (9 	imes 10^9) 	imes \frac{6.4 	imes 10^{-9}}{(0.2)^2}$.$E = \frac{9 	imes 6.4}{0.04} = \frac{57.6}{0.04} = 1440 	ext{ N C}^{-1}$.

$4 \times 10^{10}$ electrons are removed from a neutral metal sphere of diameter $20 \text{ cm}$ placed in air. The magnitude of the electric field (in $\text{N C}^{-1}$) at a distance of $20 \text{ cm}$ from its centre is:

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