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(A) Given that there are $10$ identical cells connected in series,each with electromotive force $E$ and internal resistance $r$. Total electromotive f

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$3$

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(A) Given that there are $10$ identical cells connected in series,each with electromotive force $E$ and internal resistance $r$. Total electromotive force of the circuit $= 10 E$. Total internal resistance of the circuit $= 10 r$. Using Ohm's law,the current $I$ flowing through the circuit is given by $I = \frac{	ext{Total EMF}}{	ext{Total Resistance}} = \frac{10 E}{10 r} = \frac{E}{r}$. The potential difference $V$ across $3$ cells is the sum of the potential drops across them. For $3$ cells in series,the total internal resistance is $3 r$. The potential difference across these $3$ cells is $V = I 	imes (3 r)$. Substituting the value of $I$,we get $V = \frac{E}{r} 	imes 3 r = 3 E$.

$10$ identical cells,each of potential $E$ and internal resistance $r$,are connected in series to form a closed circuit. What is the potential difference across any $3$ cells (in $E$)?

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