A transformer is used to light a 100 ,W-110 , | vedclass

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Question

(A) Given: Output power $(P_{out})$ = $100 \,W$, Input voltage $(V_{in})$ = $220 \,V$, Input current $(I_{in})$ = $0.5 \,A$.The input power $(P_{in})$

Vedclass · Accepted Answer

$90$

Vedclass · Answer

(A) Given: Output power $(P_{out})$ = $100 \,W$, Input voltage $(V_{in})$ = $220 \,V$, Input current $(I_{in})$ = $0.5 \,A$.The input power $(P_{in})$ is calculated as $P_{in} = V_{in} 	imes I_{in} = 220 \,V 	imes 0.5 \,A = 110 \,W$.The efficiency $(\eta)$ of a transformer is defined as the ratio of output power to input power: $\eta = \frac{P_{out}}{P_{in}} 	imes 100$.Substituting the values: $\eta = \frac{100 \,W}{110 \,W} 	imes 100 = \frac{10}{11} 	imes 100 \approx 90.91 \%$.Rounding to the nearest provided option, the efficiency is $90 \%$.

$A$ transformer is used to light a $100 \,W-110 \,V$ lamp from a $220 \,V$ mains. If the main current is $0.5 \,A$, the efficiency of the transformer is: (in $\%$)

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