A line passes through (2,2) and is perpendicu | vedclass

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(C) Given line is $3x+y=3$. Rewriting in slope-intercept form $y=mx+c$,we get $y=-3x+3$. Thus,the slope of this line is $m_1 = -3$. Since the required

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$4/3$

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(C) Given line is $3x+y=3$. Rewriting in slope-intercept form $y=mx+c$,we get $y=-3x+3$. Thus,the slope of this line is $m_1 = -3$. Since the required line is perpendicular to this line,its slope $m_2$ must satisfy $m_1 	imes m_2 = -1$. So,$-3 	imes m_2 = -1 \Rightarrow m_2 = 1/3$. The equation of a line passing through $(x_1, y_1)$ with slope $m$ is $(y-y_1) = m(x-x_1)$. Substituting $(x_1, y_1) = (2,2)$ and $m = 1/3$: $y-2 = 1/3(x-2)$ $y-2 = x/3 - 2/3$ $y = x/3 - 2/3 + 2$ $y = x/3 + 4/3$. The $y$-intercept is the value of $y$ when $x=0$,which is $4/3$.

$A$ line passes through $(2,2)$ and is perpendicular to the line $3x+y=3$. Its $y$-intercept is:

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