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Question

(C) For a charged spherical shell of radius $R = 10 \,cm$ carrying charge $q$:$1$. Inside the shell $(r < R)$, the electric potential is constant and

Vedclass · Accepted Answer

$V_{1} = V_{2} > V_{3}$

Vedclass · Answer

(C) For a charged spherical shell of radius $R = 10 \,cm$ carrying charge $q$:$1$. Inside the shell $(r $2$. Outside the shell $(r > R)$, the potential varies inversely with distance: $V = \frac{1}{4 \pi \varepsilon_{0}} \frac{q}{r}$.Given distances are $r_{1} = 5 \,cm$, $r_{2} = 10 \,cm$, and $r_{3} = 15 \,cm$.Since $r_{1} For $r_{3} = 15 \,cm$, $V_{3} = \frac{1}{4 \pi \varepsilon_{0}} \frac{q}{15}$.Comparing the values, since $15 > 10$, it follows that $\frac{q}{15} Thus, the correct relation is $V_{1} = V_{2} > V_{3}$.

$A$ spherical shell of radius $10 \,cm$ is carrying a charge $q$. If the electric potential at distances $5 \,cm$, $10 \,cm$, and $15 \,cm$ from the centre of the spherical shell is $V_{1}$, $V_{2}$, and $V_{3}$ respectively, then:

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