(B) The formula for the percentage of nitrogen in the Kjeldahl method is: $\text{Percentage of Nitrogen} = \frac{1.4 \times N \times V}{W}$ Where: $N

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(B) The formula for the percentage of nitrogen in the Kjeldahl method is: $\text{Percentage of Nitrogen} = \frac{1.4 \times N \times V}{W}$ Where: $N = \text{Normality of } HCl = 1 \ N$ $V = \text{Volume of } HCl \text{ consumed} = 30 \ cm^3$ $W = \text{Weight of organic compound} = 1.2 \ g$ Substituting the values: $\text{Percentage of Nitrogen} = \frac{1.4 \times 1 \times 30}{1.2} = \frac{42}{1.2} = 35 \%$

Class 11 Chemistry 8-3.Organic Chemistry : Purification and characterization Quantitative Analysis

Medium

$1.2 \ g$ of an organic compound on Kjeldahlization liberates ammonia which consumes $30 \ cm^3$ of $1 \ N \ HCl$. The percentage of nitrogen in the organic compound is:

KCET 2011 All KCET

A
$30$
B
$35$
C
$46.67$
D
$20.8$

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8-3.Organic Chemistry : Purification and characterization

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Quantitative Analysis

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$1.2 \ g$ of an organic compound on Kjeldahlization liberates ammonia which consumes $30 \ cm^3$ of $1 \ N \ HCl$. The percentage of nitrogen in the organic compound is:

Similar Questions

Kjeldahl's method is used in the estimation of:

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When $0.15 \ g$ of an organic compound was analyzed using the Carius method for the estimation of bromine,$0.2397 \ g$ of $AgBr$ was obtained. The percentage of bromine in the organic compound is $.....$ (Nearest integer).[Atomic mass: Silver $= 108$,Bromine $= 80$]

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When $0.15 \ g$ of an organic compound was analyzed using the Carius method for the estimation of bromine,$0.2397 \ g$ of $AgBr$ was obtained. The percentage of bromine in the organic compound is $.....$ (Nearest integer).
[Atomic mass: Silver $= 108$,Bromine $= 80$]