$C_6H_5CH_2Cl$ $\xrightarrow{\text{Alc. } NH_3} A$ $\xrightarrow{2 CH_3Cl} B$. The product $B$ is

• A
  $N, N$-dimethylphenylmethanamine
• B
  $N, N$-dimethylbenzenamine
• C
  $N$-benzyl-$N$-methylmethanamine
• D
  phenyl-$N, N$-dimethylmethanamine