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(D) The force per unit length between two parallel conductors carrying currents $I_1$ and $I_2$ separated by distance $r$ is given by $f = \frac{\mu_0

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towards $B$ equal to $0.6 	imes 10^{-5} \, N$

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(D) The force per unit length between two parallel conductors carrying currents $I_1$ and $I_2$ separated by distance $r$ is given by $f = \frac{\mu_0 I_1 I_2}{2 \pi r}$. The force is attractive if currents are in the same direction.Force on $C$ due to $A$ $(F_{AC})$:$F_{AC} = \frac{\mu_0 I_A I_C L}{2 \pi r_{AC}} = \frac{2 	imes 10^{-7} 	imes 2 	imes 3 	imes 1}{0.05} = \frac{12 	imes 10^{-7}}{0.05} = 2.4 	imes 10^{-5} \, N$ (towards $A$, attractive).Force on $C$ due to $B$ $(F_{BC})$:$F_{BC} = \frac{\mu_0 I_B I_C L}{2 \pi r_{BC}} = \frac{2 	imes 10^{-7} 	imes 4 	imes 3 	imes 1}{0.08} = \frac{24 	imes 10^{-7}}{0.08} = 3.0 	imes 10^{-5} \, N$ (towards $B$, attractive).Since $F_{BC}  >  F_{AC}$, the net force is $F_{net} = F_{BC} - F_{AC} = (3.0 - 2.4) 	imes 10^{-5} \, N = 0.6 	imes 10^{-5} \, N$ towards $B$.

$A$ and $B$ are two infinitely long straight parallel conductors. $C$ is another straight conductor of length $1 \, m$ kept parallel to $A$ and $B$ as shown in the figure. Then the force experienced by $C$ is

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