$XeF_{6}$ on partial hydrolysis gives a compound $X$,which has square pyramidal geometry. '$X$' is

  • A
    $XeO_{3}$
  • B
    $XeO_{4}$
  • C
    $XeOF_{4}$
  • D
    $XeO_{2}F_{2}$

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The difference in the oxidation state of $Xe$ between the oxidized product of $Xe$ formed on complete hydrolysis of $XeF_4$ and $XeF_4$ is

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