(B) Given: $p_1 = 2 \ atm$,$T_1 = 25 + 273 = 298 \ K$,$T_2 = 323 + 273 = 596 \ K$. Let initial volume $V_1 = V$. Then final volume $V_2 = \frac{2}{3}

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(B) Given: $p_1 = 2 \ atm$,$T_1 = 25 + 273 = 298 \ K$,$T_2 = 323 + 273 = 596 \ K$. Let initial volume $V_1 = V$. Then final volume $V_2 = \frac{2}{3} V$. Using the combined gas law: $\frac{p_1 V_1}{T_1} = \frac{p_2 V_2}{T_2}$. Substituting the values: $\frac{2 \times V}{298} = \frac{p_2 \times (2/3) V}{596}$. $p_2 = \frac{2 \times 596}{298 \times (2/3)} = \frac{2 \times 2}{2/3} = 2 \times 3 = 6 \ atm$.

Class 11 Chemistry States of Matter Ideal gas equation and Related gas laws

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$A$ gas at a pressure of $2 \ atm$ is heated from $25^{\circ} C$ to $323^{\circ} C$ and simultaneously compressed to $\frac{2}{3}$ of its original volume. What is the final pressure (in $atm$)?

KCET 2023 All KCET

A
$1.33$
B
$6$
C
$2$
D
$4$

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States of Matter

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Ideal gas equation and Related gas laws

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$A$ gas at a pressure of $2 \ atm$ is heated from $25^{\circ} C$ to $323^{\circ} C$ and simultaneously compressed to $\frac{2}{3}$ of its original volume. What is the final pressure (in $atm$)?

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$A$ gas at $10^{\circ}C$ occupies a volume of $283 \text{ mL}$. If it is heated to $20^{\circ}C$ at constant pressure, what is the new volume of the gas (in $\text{ mL}$)?

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