A body of mass 10 mg is moving with a veloci | vedclass

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(C) Given: Mass $m = 10 \ mg = 10 	imes 10^{-6} \ kg = 10^{-5} \ kg$. Velocity $v = 100 \ ms^{-1} = 10^2 \ ms^{-1}$. Planck's constant $h = 6.63 	im

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$6.63 	imes 10^{-31} \ m$

Vedclass · Answer

(C) Given: Mass $m = 10 \ mg = 10 	imes 10^{-6} \ kg = 10^{-5} \ kg$. Velocity $v = 100 \ ms^{-1} = 10^2 \ ms^{-1}$. Planck's constant $h = 6.63 	imes 10^{-34} \ Js$. Using the de-Broglie wavelength formula: $\lambda = \frac{h}{mv}$. Substituting the values: $\lambda = \frac{6.63 	imes 10^{-34}}{10^{-5} 	imes 10^2} = \frac{6.63 	imes 10^{-34}}{10^{-3}} = 6.63 	imes 10^{-31} \ m$.

$A$ body of mass $10 \ mg$ is moving with a velocity of $100 \ ms^{-1}$. The wavelength of de-Broglie wave associated with it would be $(h=6.63 \times 10^{-34} \ Js)$.

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