A glass tube is open at both ends. A tuning f | vedclass

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(A) For an open organ pipe of length $l$,the fundamental frequency is given by $f = \frac{v}{2l}$,where $v$ is the speed of sound in air.When the tube

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$f^{\prime} = f$

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(A) For an open organ pipe of length $l$,the fundamental frequency is given by $f = \frac{v}{2l}$,where $v$ is the speed of sound in air.When the tube is placed vertically in water such that half its length is submerged,it acts as a closed organ pipe of length $l' = \frac{l}{2}$.The fundamental frequency of a closed organ pipe is given by $f' = \frac{v}{4l'}$.Substituting $l' = \frac{l}{2}$ into the expression for $f'$,we get:$f' = \frac{v}{4(l/2)} = \frac{v}{2l}$.Comparing this with the initial frequency $f = \frac{v}{2l}$,we find that $f' = f$.

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