A body of mass m_1 = 4 kg moves at 5 hat{i} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The velocity of the centre of mass $(v_{CM})$ is given by the formula: $v_{CM} = \frac{m_1 v_1 + m_2 v_2}{m_1 + m_2}$.Substituting the given value

Vedclass · Accepted Answer

$\frac{400}{3} \ J$

Vedclass · Answer

(C) The velocity of the centre of mass $(v_{CM})$ is given by the formula: $v_{CM} = \frac{m_1 v_1 + m_2 v_2}{m_1 + m_2}$.Substituting the given values: $v_{CM} = \frac{4 	imes 5 \hat{i} + 2 	imes 10 \hat{i}}{4 + 2}$.$v_{CM} = \frac{20 \hat{i} + 20 \hat{i}}{6} = \frac{40 \hat{i}}{6} = \frac{20}{3} \hat{i} \ m/s$.The kinetic energy of the centre of mass is given by $K = \frac{1}{2} M v_{CM}^2$,where $M = m_1 + m_2 = 6 \ kg$.$K = \frac{1}{2} 	imes 6 	imes (\frac{20}{3})^2$.$K = 3 	imes \frac{400}{9} = \frac{400}{3} \ J$.

$A$ body of mass $m_1 = 4 \ kg$ moves at $5 \hat{i} \ m/s$ and another body of mass $m_2 = 2 \ kg$ moves at $10 \hat{i} \ m/s$. The kinetic energy of the centre of mass is

Similar Questions

Which of the following is a favourable factor for cation formation?

If $\sin {\theta _1} + \sin {\theta _2} + \sin {\theta _3} = 3,$ then $\cos {\theta _1} + \cos {\theta _2} + \cos {\theta _3} = $

The arithmetic mean of a set of observations is $\bar{X}$. If each observation is divided by $\alpha$ and then increased by $10$,then the mean of the new series is:

$Mg$ forms $Mg^{2+}$ but not $Mg^+$. The reason is ........

During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its absolute temperature. The ratio ${C_p}/{C_v}$ for the gas is

Vedclass Test Series

Exam Paper Generator

Online Exam Module