$A$ light body of momentum $P_L$ and a heavy body of momentum $P_H$,both have the same kinetic energy,then:

Two bodies of masses $m$ and $2m$ have the same momentum. Their respective kinetic energies $E_1$ and $E_2$ are in the ratio:

When the mass and speed of the body are doubled,the kinetic energy of the body

If the kinetic energy of a body moving with a velocity of $(2 \hat{i} + 3 \hat{j} - 4 \hat{k}) \text{ m/s}$ is $87 \text{ J}$, then the mass of the body is: (in $\text{ kg}$)

$A$ running man has half the kinetic energy of a boy who has half the man's mass. The man speeds up by $1 \, m/s$ so that his kinetic energy becomes equal to that of the boy. The original speed of the man is:

If the momentum of a body is increased by $100\%$,then the percentage increase in the kinetic energy is ............ $\%$