R longrightarrow P is a first order reaction. | vedclass

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Question

(B) The average rate of reaction is given by the formula: $	ext{Average Rate} = -\frac{\Delta[R]}{\Delta t}$.Given,$\Delta[R] = [R]_2 - [R]_1 = 0.03

Vedclass · Accepted Answer

$4.167 	imes 10^{-6}$

Vedclass · Answer

(B) The average rate of reaction is given by the formula: $	ext{Average Rate} = -\frac{\Delta[R]}{\Delta t}$.Given,$\Delta[R] = [R]_2 - [R]_1 = 0.03 - 0.04 = -0.01 \ mol \ L^{-1}$.Given,$\Delta t = 40 \ min = 40 	imes 60 \ s = 2400 \ s$.Substituting the values: $	ext{Average Rate} = -\frac{-0.01}{2400} = \frac{0.01}{2400} \ mol \ L^{-1} \ s^{-1}$.$	ext{Average Rate} = \frac{1 	imes 10^{-2}}{24 	imes 10^2} = \frac{1}{24} 	imes 10^{-4} \approx 0.04167 	imes 10^{-4} = 4.167 	imes 10^{-6} \ mol \ L^{-1} \ s^{-1}$.

Time $(s)$	$0$	$100$	$200$	$300$	$400$	$700$	$800$
$[C_4H_9Cl]$ $(mol \, L^{-1})$	$0.100$	$0.082$	$0.067$	$0.055$	$0.044$	$0.021$	$0.017$

$R \longrightarrow P$ is a first order reaction. The concentration of $R$ changed from $0.04$ to $0.03 \ mol \ L^{-1}$ in $40 \ min$. What is the average velocity of the reaction in $mol \ L^{-1} \ s^{-1}$?

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