A signal of frequency 10 kHz and peak voltage | vedclass

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(A) Given:Frequency of the modulating signal,$f_s = 10 kHz$.Carrier frequency,$f_c = 1 MHz = 1000 kHz$.In amplitude modulation,the side-band frequenci

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$1010, 990$

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(A) Given:Frequency of the modulating signal,$f_s = 10 kHz$.Carrier frequency,$f_c = 1 MHz = 1000 kHz$.In amplitude modulation,the side-band frequencies are given by the formula:$f_{side} = f_c \pm f_s$Substituting the values:Upper side-band frequency $(f_{USB})$ = $f_c + f_s = 1000 kHz + 10 kHz = 1010 kHz$.Lower side-band frequency $(f_{LSB})$ = $f_c - f_s = 1000 kHz - 10 kHz = 990 kHz$.Therefore,the side-band frequencies are $1010 kHz$ and $990 kHz$.

$A$ signal of frequency $10 kHz$ and peak voltage $10 V$ is used to amplitude modulate a carrier of frequency $1 MHz$ and peak voltage $20 V$. The side-band frequencies in $kHz$ are

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