A coordination compound is made of Co^{3+},NH | vedclass

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Question

(A) Since no precipitate of $AgCl$ is obtained on treating the compound with silver nitrate,it means no $Cl^{-}$ ions are available outside the coordi

Vedclass · Accepted Answer

$[Co(NH_3)_3 Cl_3], 6$

Vedclass · Answer

(A) Since no precipitate of $AgCl$ is obtained on treating the compound with silver nitrate,it means no $Cl^{-}$ ions are available outside the coordination sphere.Thus,all $Cl^{-}$ ions must be present inside the coordination sphere.The correct formula of the coordination compound is $[Co(NH_3)_3 Cl_3]$.Since the central metal $Co^{3+}$ forms six coordination bonds with the ligands,the secondary valency is $6$.

$A$ coordination compound is made of $Co^{3+}$,$NH_3$,and $Cl^{-}$. $A$ $0.1 \ M$ solution of this complex when treated with excess silver nitrate gave no precipitate. The formula of the complex and secondary valency of metal are respectively.

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