(D) Given: $E_1 = 1.2 \ V$,$r_1 = 2 \ \Omega$,$E_2 = 1.5 \ V$,$r_2 = 1 \ \Omega$. When two cells are connected in parallel with like poles together,th

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(D) Given: $E_1 = 1.2 \ V$,$r_1 = 2 \ \Omega$,$E_2 = 1.5 \ V$,$r_2 = 1 \ \Omega$. When two cells are connected in parallel with like poles together,the equivalent emf $E_{\text{eq}}$ is given by the formula: $E_{\text{eq}} = \frac{\frac{E_1}{r_1} + \frac{E_2}{r_2}}{\frac{1}{r_1} + \frac{1}{r_2}}$ Substituting the values: $E_{\text{eq}} = \frac{\frac{1.2}{2} + \frac{1.5}{1}}{\frac{1}{2} + \frac{1}{1}} = \frac{0.6 + 1.5}{0.5 + 1} = \frac{2.1}{1.5} = 1.4 \ V$.

Class 12 Physics Current Electricity Electric Cells and Combination of cells in Series and Parallel

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$A$ cell of emf $1.2 \ V$ and internal resistance $2 \ \Omega$ is connected in parallel to another cell of emf $1.5 \ V$ and internal resistance $1 \ \Omega$. If the like poles of the cells are connected together,the emf of the combination of the two cells is (in $V$)

AP EAMCET 2024 All AP EAMCET

A
$0.8$
B
$3.9$
C
$2.7$
D
$1.4$

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Electric Cells and Combination of cells in Series and Parallel

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$A$ cell of emf $1.2 \ V$ and internal resistance $2 \ \Omega$ is connected in parallel to another cell of emf $1.5 \ V$ and internal resistance $1 \ \Omega$. If the like poles of the cells are connected together,the emf of the combination of the two cells is (in $V$)

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In the given diagram,an ideal voltmeter $V$ reads $1.45\,V$. Then the relation between $r_1$ and $r_2$ is:

In the circuit shown,the potential difference between $A$ and $B$ is ............. $V$.

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