A maximum current of 0.5 mA can pass through | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To convert a galvanometer into a voltmeter,a high resistance $R$ must be connected in series with the galvanometer.Given:Galvanometer resistance,$

Vedclass · Accepted Answer

$19985$

Vedclass · Answer

(D) To convert a galvanometer into a voltmeter,a high resistance $R$ must be connected in series with the galvanometer.Given:Galvanometer resistance,$G = 15 \ \Omega$Full-scale deflection current,$I_g = 0.5 \ mA = 0.5 	imes 10^{-3} \ A = 5 	imes 10^{-4} \ A$Required voltage range,$V = 10 \ V$The formula for the series resistance $R$ is given by:$V = I_g(R + G)$$R + G = \frac{V}{I_g}$$R = \frac{V}{I_g} - G$Substituting the values:$R = \frac{10}{5 	imes 10^{-4}} - 15$$R = 2 	imes 10^4 - 15$$R = 20000 - 15 = 19985 \ \Omega$Therefore,the required resistance is $19985 \ \Omega$.

$A$ maximum current of $0.5 \ mA$ can pass through a galvanometer of resistance $15 \ \Omega$. The resistance to be connected in series to the galvanometer to convert it into a voltmeter of range $0-10 \ V$ is (in $\Omega$)

Similar Questions

In order to increase the sensitivity of a moving coil galvanometer,one should decrease

$A$ student connects a voltmeter,an ammeter,and a resistor as shown in the circuit. If the voltmeter reading is $20 \ V$ and the ammeter reading is $4 \ A$,then the resistance $R$ will be:

The pole pieces of the magnet used in a pivoted coil galvanometer are

$A$ galvanometer of resistance $G$ has a voltage range $V_g$. The resistance required to convert it to read voltage up to $V$ is

The number of turns of the coil of a moving coil galvanometer is increased in order to increase current sensitivity by $50 \%$. The percentage change in voltage sensitivity of the galvanometer will be $..........\%$

Vedclass Test Series

Exam Paper Generator

Online Exam Module