$n$ identical resistors are taken,in which $\frac{n}{2}$ resistors are joined in series in the left gap and the remaining $\frac{n}{2}$ resistors are joined in parallel in the right gap of a metre bridge. The balancing length in $cm$ is

$A$ meter bridge setup is shown in the figure. It is used to determine an unknown resistance $R$ using a given resistor of $15\,\Omega$. The galvanometer $(G)$ shows null deflection when the tapping key is at the $43\,cm$ mark from end $A$. If the end correction for end $A$ is $2\,cm$ and for end $B$ is $1\,cm$,then the determined value of $R$ will be . . . . . . $\Omega$.

In a meter bridge experiment,the ratio of the left gap resistance to the right gap resistance is $2:3$. The balance length from the left end is (in $\,cm$)

The meter bridge shown is in a balanced position with $\frac{P}{Q} = \frac{l_{1}}{l_{2}}$. If we now interchange the positions of the galvanometer and the cell,will the bridge work? If yes,what will be the balance condition?

In a meter bridge experiment,to minimize an error due to contact resistance,

In an experiment of a meter bridge, a null point is obtained at the centre of the bridge wire. When a resistance of $10\, \Omega$ is connected in one gap, the value of resistance in the other gap is ............. $\Omega$.