$A$ uniform magnetic field $\vec{B}$ is perpendicular to the plane of a circular loop of diameter $10 \text{ cm}$ formed from a wire of diameter $2 \text{ mm}$ and resistivity $2 \times 10^{-8} \Omega \text{ m}$. If a current of $11 \text{ A}$ is to be induced in the loop, then the rate at which $\vec{B}$ is to be changed is: (in $\text{ T s}^{-1}$)

$A$ coil of $n$ turns and resistance $R \text{ } \Omega$ is connected in series with a resistance $R/4$. The combination is moved for time $t$ second through flux $\phi_1$ to $\phi_2$. The induced current in the circuit is

$A$ conducting loop of radius $\frac{10}{\sqrt{\pi}}\,cm$ is placed perpendicular to a uniform magnetic field of $0.5\,T$. The magnetic field is decreased to $zero$ in $0.5\,s$ at a steady rate. The induced emf in the circular loop at $0.25\,s$ is:

$A$ coil is placed in a magnetic field $\vec{B}$ as shown below. $A$ current is induced in the coil because $\vec{B}$ is:

An insulated copper wire of $100$ turns is wrapped around a wooden cylindrical core of the cross-sectional area $24\,cm^2$. The two ends of the wire are connected to a resistor. The total resistance in the circuit is $12\,\Omega$. If an externally applied uniform magnetic field in the core along its axis changes from $1.5\,T$ in one direction to $1.5\,T$ in the opposite direction,the charge flowing through a point in the circuit during the change of magnetic field will be $.........\,mC$.

$A$ coil of $n$ turns and resistance $R \Omega$ is connected in series with a resistance $R/4$. The combination is moved for time $t$ seconds through a magnetic flux change from $\phi_1$ to $\phi_2$. The induced current in the circuit is: