$A$ circular coil of area $0.01 \ m^2$ and $40$ turns is rotated about its vertical diameter with an angular speed of $50 \ rad \ s^{-1}$ in a uniform horizontal magnetic field of $0.05 \ T$. If the average power loss due to Joule heating is $25 \ mW$,then the closed loop resistance of the coil is: (in $\Omega$)

$A$ coil of area $25 \; cm \times 10 \; cm$ having $300$ turns is rotated in a magnetic field of $4 \times 10^{-2} \; T$ with an angular speed of $50 \; rps$. What is the maximum $emf$ induced (in $\pi \; V$)?

The number of turns in the coil of an $AC$ generator are $50$ and its cross-sectional area is $2.5 \ m^2$. This coil is revolving in a uniform magnetic field of strength $0.3 \ T$ with a uniform angular velocity of $60 \ rad \ s^{-1}$. The resistance of the circuit comprising the coil is $500 \ \Omega$. The maximum induced $emf$ and maximum current produced in the generator are:

The $e.m.f.$ induced in a coil of wire,which is rotating in a magnetic field,does not depend on

$A$ circular coil of radius $8.0 \, cm$ and $20$ turns is rotated about its vertical diameter with an angular speed of $50 \, rad \, s^{-1}$ in a uniform horizontal magnetic field of $3.0 \times 10^{-2} \, T$. The maximum $emf$ induced in the coil will be $\ldots \ldots \ldots \times 10^{-2} \, V$ (rounded off to the nearest integer).

$A$ coil of $200$ turns and area $0.20 \ m^2$ is rotated at half a revolution per second and is placed in a uniform magnetic field of $0.01 \ T$ perpendicular to the axis of rotation of the coil. The maximum voltage generated in the coil is $\frac{2 \pi}{\beta} \ V$. The value of $\beta$ is . . . . . .