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(B) Given that,two charges $q_1 = 20 \mu C$ and $q_2 = 10 \mu C$ are separated by a distance $d = 50 \ m$.Work done $W$ in bringing a unit positive ch

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$10.8 	imes 10^3 \ J$

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(B) Given that,two charges $q_1 = 20 \mu C$ and $q_2 = 10 \mu C$ are separated by a distance $d = 50 \ m$.Work done $W$ in bringing a unit positive charge $q = 1 \ C$ from infinity to the midpoint $M$ is given by $W = qV$,where $V$ is the electric potential at point $M$.The potential at $M$ due to charges $q_1$ and $q_2$ is $V = \frac{K q_1}{(d/2)} + \frac{K q_2}{(d/2)} = \frac{2K}{d} (q_1 + q_2)$.Substituting the values:$W = 1 	imes \frac{2 	imes (9 	imes 10^9)}{50} 	imes (20 + 10) 	imes 10^{-6} \ J$$W = \frac{18 	imes 10^9}{50} 	imes 30 	imes 10^{-6} \ J$$W = \frac{540 	imes 10^3}{50} \ J = 10.8 	imes 10^3 \ J$.

$A$ unit positive charge has to be brought from infinity to a midpoint between two charges $20 \mu C$ and $10 \mu C$ separated by a distance of $50 \ m$. How much work will be required?

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