A block of mass 10 kg is placed on a horizon | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let $M = 10 \ kg$ be the mass on the horizontal surface and $m$ be the mass of the hanging block.Since the system is released from rest,the initia

Vedclass · Accepted Answer

$11.11$

Vedclass · Answer

(B) Let $M = 10 \ kg$ be the mass on the horizontal surface and $m$ be the mass of the hanging block.Since the system is released from rest,the initial velocity $u = 0$.The distance covered by the hanging block is $s = 2 \ m$ in time $t = 2 \ s$.Using the equation of motion $s = ut + \frac{1}{2}at^2$:$2 = 0 + \frac{1}{2} 	imes a 	imes (2)^2$$2 = 2a \Rightarrow a = 1 \ ms^{-2}$.Now,applying Newton's second law to the system:For the hanging block: $mg - T = ma$For the block on the surface: $T = Ma$Adding these two equations: $mg = (M + m)a$$m(g - a) = Ma$$m(10 - 1) = 10 	imes 1$$9m = 10 \Rightarrow m = \frac{10}{9} \ kg \approx 1.11 \ kg$.The weight of the hanging block is $W = mg = \frac{10}{9} 	imes 10 = \frac{100}{9} \ N \approx 11.11 \ N$.

Similar Questions

The maximum acceleration with which a body of mass $200 \, kg$ is lowered into a well using a rope having a breaking force of $50 \, kg$-wt is (Acceleration due to gravity $= 10 \, ms^{-2}$) (in $ \, ms^{-2}$)

Three blocks $A, B$ and $C$ are suspended as shown in the figure. The mass of each block $A$ and $C$ is $m$. If the system is in equilibrium and the mass of $B$ is $M$,then:

Two masses $2 \, kg$ and $3 \, kg$ are attached to the ends of a string passed over a pulley fixed at the top. The tension and acceleration are:

Three blocks of masses $4\,kg$,$6\,kg$ and $8\,kg$ are hanging over a fixed pulley as shown. The tension in the string connecting the $8\,kg$ and $4\,kg$ blocks is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module