A motorcyclist wants to drive in horizontal c | vedclass

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(B) The forces acting on the motorcyclist are the gravitational force $mg$ acting downwards and the frictional force $f = \mu N$ acting upwards.For th

Vedclass · Accepted Answer

$0.64$

Vedclass · Answer

(B) The forces acting on the motorcyclist are the gravitational force $mg$ acting downwards and the frictional force $f = \mu N$ acting upwards.For the motorcyclist to stay in a horizontal circle,the normal force $N$ provided by the wall acts as the centripetal force,so $N = \frac{mv^2}{r}$.To prevent the motorcyclist from sliding down,the frictional force must balance the gravitational force: $f = mg$.Substituting $f = \mu N$,we get $\mu N = mg$.$\mu \left(\frac{mv^2}{r}ight) = mg$.$\mu = \frac{gr}{v^2}$.Given $g = 10 \ m \ s^{-2}$,$r = 8.0 \ m$,and $v = 5 \sqrt{5} \ m \ s^{-1}$.$\mu = \frac{10 	imes 8}{(5 \sqrt{5})^2} = \frac{80}{25 	imes 5} = \frac{80}{125}$.$\mu = 0.64$.

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