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(A) The magnetic field $B$ at a distance $r$ from a long straight current-carrying wire is given by the formula:$B = \frac{\mu_0 I}{2 \pi r}$Given:$I

Vedclass · Accepted Answer

$6 	imes 10^{-6} \,T$, towards South

Vedclass · Answer

(A) The magnetic field $B$ at a distance $r$ from a long straight current-carrying wire is given by the formula:$B = \frac{\mu_0 I}{2 \pi r}$Given:$I = 150 \,A$$r = 5 \,m$$\mu_0 = 4 \pi 	imes 10^{-7} \,T \cdot m/A$Substituting the values:$B = \frac{4 \pi 	imes 10^{-7} 	imes 150}{2 \pi 	imes 5}$$B = 2 	imes 10^{-7} 	imes 30$$B = 60 	imes 10^{-7} \,T = 6 	imes 10^{-6} \,T$According to the Right-Hand Thumb Rule, if the current flows from East to West, the magnetic field lines circle the wire. Directly below the wire, the direction of the magnetic field points towards the South.

$A$ horizontal overhead powerline is at a height of $5 \,m$ from the ground and carries a current of $150 \,A$ from East to West. The magnetic field directly below it on the ground is

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