A body of mass 1.5 kg is moving towards sout | vedclass

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(B) Given: Mass $m = 1.5 \ kg$,initial velocity $\overrightarrow{v} = -8 \hat{j} \ ms^{-1}$ (towards south),force $\overrightarrow{F} = 6 \hat{i} \ N$

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(B) Given: Mass $m = 1.5 \ kg$,initial velocity $\overrightarrow{v} = -8 \hat{j} \ ms^{-1}$ (towards south),force $\overrightarrow{F} = 6 \hat{i} \ N$ (towards east),time $t = 3 \ s$.Acceleration $\overrightarrow{a} = \frac{\overrightarrow{F}}{m} = \frac{6}{1.5} \hat{i} = 4 \hat{i} \ ms^{-2}$.Using the equation of motion for displacement: $\overrightarrow{s} = \overrightarrow{v}t + \frac{1}{2} \overrightarrow{a}t^2$.Substituting the values: $\overrightarrow{s} = (-8 \hat{j})(3) + \frac{1}{2}(4 \hat{i})(3)^2$.$\overrightarrow{s} = -24 \hat{j} + 2(9) \hat{i} = 18 \hat{i} - 24 \hat{j} \ m$.The magnitude of displacement is $S = |\overrightarrow{s}| = \sqrt{(18)^2 + (-24)^2} = \sqrt{324 + 576} = \sqrt{900} = 30 \ m$.

$A$ body of mass $1.5 \ kg$ is moving towards south with a uniform velocity of $8 \ ms^{-1}$. $A$ force of $6 \ N$ is applied to the body towards east. The displacement of the body $3 \ s$ after the application of the force is (in $m$)

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