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(B) The initial mass attached to the spring is $m_1 = 1 \,kg$. The mass hitting it is $m_2 = 0.5 \,kg$.After the collision, the two bodies move togeth

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$\frac{10}{\pi} \,Hz$

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(B) The initial mass attached to the spring is $m_1 = 1 \,kg$. The mass hitting it is $m_2 = 0.5 \,kg$.After the collision, the two bodies move together as a single system with a total mass $M = m_1 + m_2 = 1 + 0.5 = 1.5 \,kg$.The force constant of the spring is $k = 600 \,N \,m^{-1}$.The angular frequency of the oscillation for a spring-mass system is given by $\omega = \sqrt{\frac{k}{M}}$.Substituting the values: $\omega = \sqrt{\frac{600}{1.5}} = \sqrt{400} = 20 \,rad \,s^{-1}$.The frequency of oscillation $f$ is related to angular frequency by $f = \frac{\omega}{2\pi}$.Therefore, $f = \frac{20}{2\pi} = \frac{10}{\pi} \,Hz$.

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