Class 11MathematicsTrigonometrical Ratios, Functions and IdentitiesFundamental trigonometrical ratios and functions, Trigonometrical ratio of allied angles
Easy$\frac{\sin x}{1+\cos x} + \frac{1+\cos x}{\sin x} = ?$
- A$2 \sec x$
- B$2 \operatorname{cosec} x$
- C$\tan 2x$
- D$\sin 2x$
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Similar Questions
If $x \cos \theta = y \cos \left(\theta + \frac{2 \pi}{3}\right) = z \cos \left(\theta + \frac{4 \pi}{3}\right)$,then $\frac{1}{x} + \frac{1}{y} + \frac{1}{z} = $
DifficultAP EAMCET 2021
View SolutionSuppose $ABC$ is a triangle and $D, E$ are points on the sides $AB$ and $AC$ respectively. If $AD : AB = 3 : 5$ and $AE : AC = 2 : 3$,then the ratio of the areas of the triangles $ABC$ and $ADE$ lies in the interval.
$\cos ^2\left(\frac{7 \pi}{8}\right)+\cos ^2\left(\frac{5 \pi}{8}\right)+\cos ^2\left(\frac{3 \pi}{8}\right)+\cos ^2\left(\frac{\pi}{8}\right)=$
If $\cot \theta = -\frac{2}{3}$ and $\theta$ does not lie in the $4^{\text{th}}$ quadrant,then $\frac{(5 \sin \theta + \cos \theta)^2}{\tan \theta + \cot \theta} = $
If $5 \tan \theta = 4$,then $\frac{5 \sin \theta - 3 \cos \theta}{5 \sin \theta + 2 \cos \theta} = $
Easy
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