sin 120^{circ} cos 150^{circ} - cos 240^{circ | vedclass

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(B) We use the values of trigonometric functions for allied angles:$\sin 120^{\circ} = \sin(180^{\circ} - 60^{\circ}) = \sin 60^{\circ} = \frac{\sqrt{

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$-1$

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(B) We use the values of trigonometric functions for allied angles:$\sin 120^{\circ} = \sin(180^{\circ} - 60^{\circ}) = \sin 60^{\circ} = \frac{\sqrt{3}}{2}$$\cos 150^{\circ} = \cos(180^{\circ} - 30^{\circ}) = -\cos 30^{\circ} = -\frac{\sqrt{3}}{2}$$\cos 240^{\circ} = \cos(180^{\circ} + 60^{\circ}) = -\cos 60^{\circ} = -\frac{1}{2}$$\sin 330^{\circ} = \sin(360^{\circ} - 30^{\circ}) = -\sin 30^{\circ} = -\frac{1}{2}$Substituting these values into the expression:$\left(\frac{\sqrt{3}}{2}\right) \left(-\frac{\sqrt{3}}{2}\right) - \left(-\frac{1}{2}\right) \left(-\frac{1}{2}\right)$$= -\frac{3}{4} - \frac{1}{4}$$= -\frac{4}{4} = -1$

$\sin 120^{\circ} \cos 150^{\circ} - \cos 240^{\circ} \sin 330^{\circ}$ is equal to :

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