{ }^{34}C_{10} + 3 cdot { }^{34}C_{9} + 3 cdo | vedclass

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(C) Using the identity ${ }^{n}C_{r} + { }^{n}C_{r-1} = { }^{n+1}C_{r}$,we can rewrite the expression as: ${ }^{34}C_{10} + { }^{34}C_{9} + 2 \cdot {

Vedclass · Accepted Answer

${ }^{37}C_{10}$

Vedclass · Answer

(C) Using the identity ${ }^{n}C_{r} + { }^{n}C_{r-1} = { }^{n+1}C_{r}$,we can rewrite the expression as: ${ }^{34}C_{10} + { }^{34}C_{9} + 2 \cdot { }^{34}C_{9} + 2 \cdot { }^{34}C_{8} + { }^{34}C_{8} + { }^{34}C_{7} = $ $({ }^{34}C_{10} + { }^{34}C_{9}) + 2({ }^{34}C_{9} + { }^{34}C_{8}) + ({ }^{34}C_{8} + { }^{34}C_{7}) = $ ${ }^{35}C_{10} + 2 \cdot { }^{35}C_{9} + { }^{35}C_{8} = $ ${ }^{35}C_{10} + { }^{35}C_{9} + { }^{35}C_{9} + { }^{35}C_{8} = $ ${ }^{36}C_{10} + { }^{36}C_{9} = { }^{37}C_{10}$

${ }^{34}C_{10} + 3 \cdot { }^{34}C_{9} + 3 \cdot { }^{34}C_{8} + { }^{34}C_{7} = $

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