$A$ prism is made up of material of refractive index $\sqrt{3}$. The angle of the prism is $A$. If the angle of minimum deviation is equal to the angle of the prism,then the value of $A$ is: (in $^{\circ}$)

$A$ thin glass prism has a refractive index of $1.5$. The correct relation between the angle of minimum deviation $(\delta_m)$ and the angle of the prism $(A)$ is given by the formula for a thin prism. If the angle of refraction is $r$, find the correct relation between the angle of minimum deviation $(\delta_m)$ and the angle of refraction $(r)$ for a thin prism.

$A$ prism has a refractive index $\sqrt{3/2}$ and a refracting angle of $90^o$. Find the minimum deviation produced by the prism in degrees.

$A$ ray of light is incident on a right-angled isosceles prism parallel to its base as shown in the figure. The refractive index of the material of the prism is $\sqrt{2}$. Which of the following statement$(s)$ is/are true?

The angle of deviation $(\delta)$ vs angle of incidence $(i)$ is plotted for a prism. Pick the correct statement:-

$A$ prism of refractive index $n_{1}$ and another prism of refractive index $n_{2}$ are stuck together (as shown in the figure). $n_{1}$ and $n_{2}$ depend on $\lambda$, the wavelength of light, according to the relation:
${n}_{1}=1.2+\frac{10.8 \times 10^{-14}}{\lambda^{2}} \text{ and } {n}_{2}=1.45+\frac{1.8 \times 10^{-14}}{\lambda^{2}}$
The wavelength for which rays incident at any angle on the interface $BC$ pass through without bending at that interface will be $....\,nm.$