H_2O_2 with KMnO_4 in acidic medium gives a m | vedclass

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(A) In acidic medium,$KMnO_4$ reacts with $H_2O_2$ to form $Mn^{2+}$ ions. The reaction is: $2MnO_4^- + 6H^+ + 5H_2O_2 \rightarrow 2Mn^{2+} + 5O_2 + 8

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$+2, +4$

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(A) In acidic medium,$KMnO_4$ reacts with $H_2O_2$ to form $Mn^{2+}$ ions. The reaction is: $2MnO_4^- + 6H^+ + 5H_2O_2 \rightarrow 2Mn^{2+} + 5O_2 + 8H_2O$. Thus,the oxidation state of $Mn$ in $X$ $(Mn^{2+})$ is $+2$.In basic medium,$KMnO_4$ reacts with $H_2O_2$ to form $MnO_2$. The reaction is: $2MnO_4^- + 3H_2O_2 \rightarrow 2MnO_2 + 3O_2 + 2OH^- + 2H_2O$. In $MnO_2$,the oxidation state of $Mn$ is calculated as: $x + 2(-2) = 0$,so $x = +4$. Thus,the oxidation state of $Mn$ in $Y$ $(MnO_2)$ is $+4$.Therefore,the oxidation states of $Mn$ in $X$ and $Y$ are $+2$ and $+4$ respectively.

$H_2O_2$ with $KMnO_4$ in acidic medium gives a manganese compound '$X$' and in basic medium gives another manganese compound '$Y$'. The oxidation state of manganese in $X$ and $Y$,respectively are

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