A and B atoms in a crystal are positioned at | vedclass

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(A) Atoms of $A$ are placed at the corners of the unit cell. The number of corners in a cube is $8$,and the contribution of each corner atom is $\frac

Vedclass · Accepted Answer

$A B_3$

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(A) Atoms of $A$ are placed at the corners of the unit cell. The number of corners in a cube is $8$,and the contribution of each corner atom is $\frac{1}{8}$.Number of $A$ atoms $= 8 	imes \frac{1}{8} = 1$.Atoms of $B$ are placed at the face centers. The number of faces in a cube is $6$,and the contribution of each face-centered atom is $\frac{1}{2}$.Number of $B$ atoms $= 6 	imes \frac{1}{2} = 3$.Therefore,the ratio of $A:B$ is $1:3$,and the formula of the crystal is $A B_3$.

$A$ and $B$ atoms in a crystal are positioned at the corners and face centers respectively. What is the formula of the crystal?

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