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(D) When a non-volatile solute is added to a volatile solvent,the solute particles occupy some of the surface area of the solvent.This reduces the num

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$p_2 < p_1 < p_3$

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(D) When a non-volatile solute is added to a volatile solvent,the solute particles occupy some of the surface area of the solvent.This reduces the number of solvent molecules available at the surface for vaporization,leading to a decrease in vapour pressure.As the concentration of the non-volatile solute increases,the vapour pressure of the solution decreases.Given concentrations of $X$ are:$0.01 ext{ mol L}^{-1} Correspondingly,the vapour pressures are:$p_3 > p_1 > p_2$This can be rewritten as:$p_2 < p_1 < p_3$

$X$ is a non-volatile solute and $Y$ is a volatile solvent. The following vapour pressures are observed by dissolving $X$ in $Y$:
| $X / \text{mol L}^{-1}$ | $Y / \text{mm of Hg}$ |
| :--- | :--- |
| $0.10$ | $p_1$ |
| $0.25$ | $p_2$ |
| $0.01$ | $p_3$ |
The correct order of vapour pressures is:

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$X$ is a non-volatile solute and $Y$ is a volatile solvent. The following vapour pressures are observed by dissolving $X$ in $Y$:| $X / \text{mol L}^{-1}$ | $Y / \text{mm of Hg}$ || :--- | :--- || $0.10$ | $p_1$ || $0.25$ | $p_2$ || $0.01$ | $p_3$ |The correct order of vapour pressures is: