A 40 % HCl solution has density 1.2 g mL^{- | vedclass

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Question

(C) Given,density $(d)$ of $HCl$ solution $= 1.2 \ g \ mL^{-1}$.Percentage strength by mass $(w/w)$ $= 40 \%$.Molar mass of $HCl$ $(M_{HCl})$ $= 1 + 3

Vedclass · Accepted Answer

$13$

Vedclass · Answer

(C) Given,density $(d)$ of $HCl$ solution $= 1.2 \ g \ mL^{-1}$.Percentage strength by mass $(w/w)$ $= 40 \%$.Molar mass of $HCl$ $(M_{HCl})$ $= 1 + 35.5 = 36.5 \ g \ mol^{-1}$.The formula for molarity is: $	ext{Molarity} = \frac{	ext{Percentage}(w/w) 	imes d 	imes 10}{M_{HCl}}$.Substituting the values: $	ext{Molarity} = \frac{40 	imes 1.2 	imes 10}{36.5} = \frac{480}{36.5} \approx 13.15 \ M$.Therefore,the molarity is nearly $13 \ M$.

$A$ $40 \%$ $HCl$ solution has density $1.2 \ g \ mL^{-1}$. The molarity of the solution is nearly . . . . . . (in $M$)

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